This is a paragraph.

Nine-point center equals a vertex IV

Another characterization of the triangle whose nine-point center coincides with one of its vertices, namely 30^{\circ}-30^{\circ}-120^{\circ}-triangle, is discussed here.

In \triangle ABC, let \angle A=\angle C=30^{\circ} and \angle B=120^{\circ}. PROVE that \triangle ACH is equilateral, where H is the orthocenter.

See the pdf.

In \triangle ABC, suppose that \triangle ACH is equilateral, where H is the orthocenter. PROVE that \angle A=\angle C=30^{\circ} and \angle B=120^{\circ}.

Same link as above: pdf.

Takeaway

In any triangle ABC, let a,b,c be the side-lengths, H the orthocenter, O the circumcenter, and R the circumradius. Then the following statements are equivalent:

  1. a=c=R
  2. \angle A=\angle C=30^{\circ}
  3. \triangle ACH is equilateral
  4. the reflection of B over AC is O
  5. the reflection of A over BC is H and the reflection of C over AB is H

Task

  • (Aufbau) In triangle ABC, let a,b,c be the side-lengths, R the circumradius, O the circumcenter, N the nine-point center, and H the orthocenter. PROVE that the following statements are equivalent:
    1. B=N
    2. a=c=R
    3. \angle A=\angle C=30^{\circ}
    4. \triangle ACH is equilateral
    5. the reflection of B over AC is O
    6. the area K satisfies K=\frac{1}{2}ac\cos A=\frac{1}{2}ac\cos C
    7. the circle with diameter OH passes through vertices A and C
    8. radius OA is parallel to side CB and radius OC is parallel to side AB
    9. the reflection of A over BC is H and the reflection of C over AB is H
    10. AF_a is the geometric mean of BF_a and CF_a, and CF_c is the geometric mean of AF_c and BF_c. (F_a and F_c are the feet of the altitudes from A and C, respectively.)